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outputting the "position()" of parent
- To: "'XSL-List at mulberrytech dot com'" <XSL-List at mulberrytech dot com>
- Subject: outputting the "position()" of parent
- From: Justin Friedl <justin dot friedl at aspentech dot com>
- Date: Wed, 7 Jun 2000 16:50:33 -0400
- Reply-To: xsl-list at mulberrytech dot com
How do I output the posistion of the parent. I can output the position of
the current node like this:
<xsl:value-of select="position()"/>
So I thought I could do this:
<xsl:value-of select="../position()"/>
but it doesn't work.... any suggestions?
thanks in advance
Justin
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