RE: parameter setting

["vanaja gogineni" <vanaja_g at england dot com>]

Thanku

I tried like that but still

I am unable to get it, I removed

select also it is not working .

is there any other way pl suggest me.

Thanks &regards

vanaja
--

On Wed, 19 Apr 2000 09:10:22   Selva, Francis wrote:
>Well I guess the reason is you have the string 'output' as ur default value
>which overwrites your actual parameter.If you remove the select attribute,it
>will work.
>
>Francis
>
> 
>> my xsl looks like this
>> ----------------------------------------------
>> it is a top level parameter
>> 
>> <xsl:param name="param1" select="'output'"/>
>> 
>> and I am using this variable in-between
>> like this
>> 
>> <xsl:value-of select="$param1"/>
>> 
>> 
>> result is
>> 
>> "output"
>> 
>> but I want "vanaja" to be displayed
>> 
>> what is the wrong with this
>> 
>> 
>> Thanks & regards
>> 
>> Vanaja
>> 
> 
>
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


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