RE: sort, count, number, group

["Volkmann, Mark" <Mark dot Volkmann at agedwards dot com>]

Title: RE: sort, count, number, group

Thank you very much!  That worked perfectly!

-----Original Message-----
From:   Steve Tinney [SMTP:stinney@sas.upenn.edu]
Sent:   Sunday, March 12, 2000 9:05 PM
To:     xsl-list@mulberrytech.com
Subject:        Re: sort, count, number, group

> <artist>
>   <recording year="1991">
>     <name>Solace</name>
>   </recording>
>   <recording year="1999">
>     <name>Mirrorball</name>
>   </recording>
> </artist>
>
> How can I find the name of the most recent recording using XSLT?

<xsl:template match="artist">
  <xsl:for-each select="recording">
    <xsl:sort data-type="number" order="descending" select="@year"/>
    <xsl:if test="position()=1">
      <xsl:value-of select="name"/>
    </xsl:if>
  </xsl:for-each>
</xsl:template>

 Steve




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