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[Bug libc/2296] New: semval could become negative
- From: "cees at gatso dot nl" <sourceware-bugzilla at sourceware dot org>
- To: glibc-bugs at sources dot redhat dot com
- Date: 8 Feb 2006 10:57:04 -0000
- Subject: [Bug libc/2296] New: semval could become negative
- Reply-to: sourceware-bugzilla at sourceware dot org
Reading throug the semaphore manpages semget, semctl and semop I realized that
eigther the documentation is incorrect or there is a security risk.
It is possible for semval to become negative in the following way:
A semaphore is created by process #1 and initialized to 0.
Process #1 releases the semaphore and sets it to 1 using SEM_UNDO.
Process #2 attatches to the semaphore and locks it setting it to 0.
Process #1 gets killed and semval should be set to -1!
In the documentation is stated that semval is a positive integer. So it can not
become -1. But according to this scheme it should be able to.
What is the behavier of the semaphore in this sequence of events?
--
Summary: semval could become negative
Product: glibc
Version: unspecified
Status: NEW
Severity: normal
Priority: P2
Component: libc
AssignedTo: drepper at redhat dot com
ReportedBy: cees at gatso dot nl
CC: glibc-bugs at sources dot redhat dot com
http://sourceware.org/bugzilla/show_bug.cgi?id=2296
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