print char and signed char equally

[xparmenides <xparmenides at yahoo dot com>]

Hi,
According the manual, " Strings are identified as arrays of char values 
without specified signedness. Arrays of either signed char or unsigned 
char get printed as arrays of 1 byte sized integers. -fsigned-char or 
-funsigned-char gcc options have no effect as gdb defines literal string 
type "char" as char without a sign. For program code

     char var0[] = "A";
     signed char var1[] = "A";

You get during debugging

     (gdb) print var0
     $1 = "A"
     (gdb) print var1
     $2 = {65 'A', 0 '\0'}
"
But, I got a different result:

(gdb) l
1       #include <stdio.h>
2
3       int main(){
4         char var0[] = "A";
5         signed char var1[] = "A";
6         return 0;
7       }
(gdb) print var0
$3 = "A"
(gdb) print var1
$4 = "A"

It seems that print command displays a char the same as a signed char. I 
think the mannual has a bug.