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Re: How to compare $arg0 with string literal?
- From: Aleksey Midenkov <midenok at gmail dot com>
- To: Doug Evans <dje at google dot com>
- Cc: "gdb at sourceware dot org" <gdb at sourceware dot org>
- Date: Fri, 27 Mar 2015 09:35:26 +0300
- Subject: Re: How to compare $arg0 with string literal?
- Authentication-results: sourceware.org; auth=none
- References: <CAF8BazAOQC-otNoogUc92mnjoxJwt8R166tx0=7JX04qFks_+g at mail dot gmail dot com> <CADPb22Rs0pEnF73E+3E46WPHNYhqpM0Lp2gm-Kws4mbYCcKGVg at mail dot gmail dot com>
On Thu, Mar 26, 2015 at 9:28 PM, Doug Evans <dje@google.com> wrote:
> Such things are not supported in gdb's own scripting language.
> However, with a bit of Python-provided magic ($_streq):
>
> define logging
> if $argc == 1
> if $_streq("$arg0", "off")
> set logging off
> set logging file gdb.log
> else
> if $_streq("$arg0", "stop")
> set logging off
> else
> set logging $arg0
> end
> end
> else
> set logging $arg0 $arg1
> end
> show logging
> end
>
> Note that gdb's if/else syntax is a pain.
Sure thing, gdb's syntax could be a bit richer... Also, if I get this
error message does that mean that my gdb is not Python-powered?
(gdb) p $_streq("off", "off")
Invalid data type for function to be called.