Re: No source file named getopt.c.

[Fei Ding <fdingiit at gmail dot com>]

I am debugging gdb using gdb, I want to know how gdb handle the
command "gdb filename options", and I've traced to the code of
gdb/main.c, which is main.c:captured_main(), and I lost myself when
step into getopt_long_only() near line 520 (gdb-7.6)

2015-03-20 15:59 GMT+08:00 Eli Zaretskii <eliz@gnu.org>:
>> Date: Fri, 20 Mar 2015 14:09:00 +0800
>> From: Fei Ding <fdingiit@gmail.com>
>>
>> I want to set a break point on some code in getopt.c, but I just got:
>>
>> ////////////////////////////////////////////
>> (gdb) b getopt.c:100
>> No source file named getopt.c.
>> ////////////////////////////////////////////
>>
>> then, I did this to add the source directory of that code, as:
>>
>> ////////////////////////////////////////////
>> (gdb) directory /home/dingaaa/test/gdb-7.6/libiberty/
>> Source directories searched: /home/dingaaa/test/gdb-7.6/libiberty:$cdir:$cwd
>> ////////////////////////////////////////////
>>
>> but still, I get
>> ////////////////////////////////////////////
>> (gdb) b getopt.c:100
>> No source file named getopt.c.
>> ////////////////////////////////////////////
>>
>> BTW: I've changed Makefiles, with `-g -O0`
>>
>> What's the problem?
>
> You can only do this when debugging a program that has getopt.c
> compiled in.  Since you give no details on how you built that program,
> it's hard to say something more intelligent.