[Bug c++/21323] GDB thinks char16_t and char32_t are signed in C++

["palves at redhat dot com" <sourceware-bugzilla at sourceware dot org>]

https://sourceware.org/bugzilla/show_bug.cgi?id=21323

Pedro Alves <palves at redhat dot com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |palves at redhat dot com

--- Comment #1 from Pedro Alves <palves at redhat dot com> ---
Hmm, thanks.  Should be easy to fix.  I see:

/* Allocate a TYPE_CODE_INT type structure associated with GDBARCH.
   BIT is the type size in bits.  If UNSIGNED_P is non-zero, set
   the type's TYPE_UNSIGNED flag.  NAME is the type name.  */

struct type *
arch_integer_type (struct gdbarch *gdbarch,
                   int bit, int unsigned_p, const char *name)
{
...
}

static void *
gdbtypes_post_init (struct gdbarch *gdbarch)
{
...
  /* Wide character types.  */
  builtin_type->builtin_char16
    = arch_integer_type (gdbarch, 16, 0, "char16_t");
  builtin_type->builtin_char32
    = arch_integer_type (gdbarch, 32, 0, "char32_t");

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