Re: Ld : _start address ?

[Sandeep Kumar <sandeepksinha at gmail dot com>]

On 12/29/05, Ramana Radhakrishnan <ramana.r@gmail.com> wrote:
> The loader does take the entry point address from e_entry in the
> elf_header. This is the actual entry point for the program . When are
> you doing this overwriting ?
>

>
>
> --
> Ramana Radhakrishnan
>

I am trying to overwrite the e_entry on an executable's elf header and
change the flow of control with the following piece of code :


              Elf32_Ehdr *self = (Elf32_Ehdr *)0x8048000;
              printf("%x",(self)->e_entry);
              (self)->e_entry = (Elf32_Addr)0x00000000;


This piece of code is present in a pre loaaded shared library.


executing as :


#LD_PRELOAD="./lib1.so" ./a.out


But the problem is that even after changing the address of the
e_entry, the actual main function of the executable a.out is getting
executed. But if the address of this e_entry is getting changed then
how the control is finally reaching _lib_start_main and finally to
main().
I tried overwriting it with 0x0000000 still it worked.



Where does the loader takes the address of _start before passing
control to it ?



> cheers
> Ramana
>
> On 12/29/05, Sandeep Kumar <sandeepksinha@gmail.com> wrote:
> > Hello everyone,
> > Can somebody please tell me where does the loader takes the program
> > entry point address from. Its not e_entry of the elf header coz even
> > after overwriting it with some other valid address , the flow of
> > control doesn't changes.
> > Does the loader takes the address of _start from the symbol table ?
> > Then what in the case of stripped binaries.
> >
> > Please help.