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Re: m68k ELF: e_flags bit for m68000 executables?



> > If not, since I bet the m68k ABI is ownerless, can we
> > agree on a value?
> 
> How about 0x00100000 ?  [Chosen not to intersect with EF_CPU32 incase
> those two bits have extra significance not documented in the sources.
> Chosen to be higher than EF_CPU32 in case the lower bits have some
> significance in the (missing) ABI.]

Going back to the code, I assume that you mean 0x01000000,
not 0x00100000 (the latter being less than EF_CPU32).

Matt

-- 
Matt Fredette
http://mit.edu/fredette/www


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