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Re: document() loops
- From: David Carlisle <davidc at nag dot co dot uk>
- To: xsl-list at lists dot mulberrytech dot com
- Cc: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 13 Sep 2002 10:19:21 +0100
- Subject: Re: [xsl] document() loops
- References: <F226mOLSSPwQmWO2Isk00003323@hotmail.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
<xsl:for-each select="document(/univ-xml-list/univ-xml[1])">
<xsl:variable name = "element-name" select="name(.)"/>
<xsl:element name="$element-name">
</xsl:element>
</xsl:for-each>
this will create all the elements that are in the first elements..
No it won't as I said before that for-each is iterating over a single node
so it will only create one element, with name equal to teh name of teh
node selected in the xsl:for-each select=" however that node is a
document node, so has name "" so the xsl:eleemnt should generate an
error thatyou are trying to generate an element with an invalid name,
"".
David
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