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RE: insert default node if it doesn't exist
- From: Jarno dot Elovirta at nokia dot com
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Tue, 10 Sep 2002 09:34:09 +0300
- Subject: RE: [xsl] insert default node if it doesn't exist
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
> I've tried with this XSLT. Problem is that since the match
> doesn't find <c> for the 2nd both for b and g, I'll get a <c>
> for everyone of them. How can this be solved?
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="xml" version="1.0" encoding="UTF-8"
> indent="yes"/>
>
> <xsl:template match="a/*">
> <xsl:copy>
> <xsl:apply-templates
> select="@*|node()"/>
> </xsl:copy>
> <xsl:if test="not(../c)">
> <c>0</c>
> </xsl:if>
> </xsl:template>
try
<xsl:template match="a[not(c)]">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
<c>0</c>
</xsl:copy>
</xsl:template>
Jarno - In Strict Confidence: Zauberschloss (Mechanical Fairy Tale remix)
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