Re: [xsl] If nodeset does NOT include

[Jeni Tennison <jeni at jenitennison dot com>]

Hi Brian,

>> I want to call a template only if a nodeset does
>> not contain a match for a variable, ie:
>> 
>> <xsl:if test="(.//InqInfo/Member_Id != $listfor)">
>>                         <xsl:call-template 
>> name="Recipbutton">
>> 
>> where != should mean "does not include"
>> I know it's a stupid question, but I can't see a 
>> simple, straightforward way to do this.
>
> != means "does not equal"--not quite the same thing. If you want to
> test if $listfor does not exist within Member_Id, you could try:
>
> <xsl:if test="not(contains(.//InqInfo/Member_Id,$listfor))">
>   <xsl:call-template name="Recipbutton"/>
> </xsl:if>
>
> (newbie post--please correct me as necessary!)

OK :) The contains() function tests whether the first argument string
contains the second argument string. For example:

  contains('foobar', 'ob')

would be true.

What Thomas was wanting to do, I believe, is to see whether any of the
Member_Id elements in the document contain the value $listfor, and if
not then call the Recipbutton template. In other words, he wants to
test whether any of the nodes in the node set have a value that is
*equal to* $listfor. Contains() doesn't do that. He needs:

  <xsl:if test="not(.//InqInfo/Member_Id = $listfor)">
    <xsl:call-template name="Recipbutton" />
  </xsl:if>

I think.

When you pass a node set to a function that wants a string, the node
set is converted to a string by taking the value of the first node in
the node set. So your suggestion of:

  not(contains(.//InqInfo/Member_Id, $listfor))

would actually return true if the first Member_Id didn't contain the
value of the $listfor variable, and false otherwise.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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