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Re: transforming XML into XML using XSLT.
- From: Wendell Piez <wapiez at mulberrytech dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Tue, 13 Aug 2002 17:44:12 -0400
- Subject: Re: [xsl] transforming XML into XML using XSLT.
- Reply-to: xsl-list at lists dot mulberrytech dot com
Neel,
At 04:11 PM 8/13/2002, you wrote:
Is it possible to convert XML[having useful +unnecessary data ]
-----to-----> XML [having Useful data] using XSLT.Could you please help
me out with an example.
Sure:
<source>
<useful>This is an example on XSL-List</useful>
<unnecessary>It's rather pointed (unnecessarily so).</unnecessary>
</source>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- this could be a near-identity transform, but for ease of illustration
we'll just strip out the node structure instead -->
<xsl:template match="/">
<result>
<!-- this template is here so the result is actually XML, rather
than simply a well-formed external parsed entity -->
<xsl:apply-templates/>
</result>
</xsl:template>
<xsl:template match="unnecessary"/>
</xsl:stylesheet>
But I think the real answer depends on what's useful and what's
unnecessary, and how you tell the difference.
Cheers,
Wendell
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Wendell Piez mailto:wapiez@mulberrytech.com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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