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Re: stripping leading and trailing newlines from xml
- From: "Aparna Konduri" <a_konduri at lycos dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Thu, 08 Aug 2002 16:43:19 -0400
- Subject: Re: [xsl] stripping leading and trailing newlines from xml
- Organization: Lycos Mail (http://www.mail.lycos.com:80)
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hello Mike,
Suppose xml is like
-----------------------------------
\n
<xml>
<tag1> x </tag>
<tag2> y </tag>
</xml>
\n
------------------------------------
where \n is a newline. I want to have the entire format as it is, except for the leading and trailing newlines. I mean the output should be just,
-----------------------------------
<xml>
<tag1> x </tag>
<tag2> y </tag>
</xml>
------------------------------------
Is there a way in xsl to do this? I tried, normalize-space() only to find out that all the format of xml file is gone. I want to have extra spaces on all the lines, except for the first and last newlines.
Thanks for your help,
Aparna
--
On Thu, 8 Aug 2002 14:31:46
Mike Brown wrote:
>Aparna Konduri wrote:
>> Is there a way to just strip leading and trailing newlines from
>> xml using xsl or javascript?
>
>XSLT has somewhat unintuitive rules for how it handles whitespace
>and newlines. You did not provide an example of what you want to
>accomplish, so I guess you meant extraneous whitespace.
>
>An identity transform as discussed in the XSLT spec under "Copying"
>(xsl:copy), with the addition of
>
> <xsl:strip-space elements="*"/>
> <xsl:output method="xml" indent="no"/>
>
>is probably what you want.
>
> - Mike
>____________________________________________________________________________
> mike j. brown | xml/xslt: http://skew.org/xml/
> denver/boulder, colorado, usa | resume: http://skew.org/~mike/resume/
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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