AW: [xsl] An easy problem

["Thomas Bayer" <bayer at oio dot de>]

Hello Alexek,

I think the following Stylesheet will do it. Use an index for alle radio
input fields. You can create the index with xsl:key. Iterate over the index
and take only the first element for each key. To do this I used a method
called muenchs method [Correct me for the right spelling].

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";>
  <xsl:key name="radios" match="//input[@type='radio']" use="@name"/>
  <xsl:template match="form">
    <do type="accept" label="submit">
      <go href="{@action}" method="{@method}">

        <xsl:apply-templates select=".//input[@type='checkbox']"/>

        <xsl:for-each
select="//input[generate-id(.)=generate-id(key('radios', @name))]">

         <postfield name="{@name}" value="{concat('$',@name)}"/>

        </xsl:for-each>

      </go>
    </do>
    <xsl:apply-templates select="*"/>
  </xsl:template>

  <xsl:template match="input[@type='checkbox']">
    <postfield name="{@name}" value="{concat('$',@name)}"/>
  </xsl:template>

</xsl:stylesheet>

Thomas

Orientation in Objects
http://www.oio.de


> -----Ursprüngliche Nachricht-----
> Von: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]Im Auftrag von alex ek
> Gesendet: Samstag, 27. Juli 2002 16:51
> An: XSL-List@lists.mulberrytech.com
> Betreff: [xsl] An easy problem
>
>
> Hello All
> I have a problem in xslt style sheet in which i am writing
> template match for the form tag of HTML.
> I hev some thing like this in HTML
> <form method="POST" action="choice.html">
> <p>Enter the choices</p>
> <p><input type="checkbox" name="name1" checked="checked"
> />America<br />
>   <input type="checkbox" name="name2" checked="checked"
> />Europe<br />
>   <input type="checkbox" name="name3" />Asia </p>
> <p>Enter the gender</p>
>   <input type="radio" name="gender" value="mal" />male<br />
>   <input type="radio" name="gender" value="fem" /> female
> </form>
>
> And i want to convert it in this form
>
> <do label="submit" type="accept">
> <go href="choice.html" method="post">
> <postfield name="name1" value="$name1"/>
> <postfield name="name2" value="$name2"/>
> <postfield name="name3" value="$name3"/>
> <postfield name="gender" value="$gender"/>
> </go>
> </do>
>
> And the style sheet i am using is
>
>   <xsl:template match="form">
>          <do type="accept" label="submit">
>           <go href="@action" method="@method">
>            <xsl:choose>
>             <xsl:when test="input[@type='checkbox']">
>              <xsl:for-each select="input[@type='checkbox']">
>               <postfield name="@name" value="$@name">
>              </xsl:for-each>
>             </xsl:when>
>             <xsl:when test="input[@type='radio']>
>              <postfield name=@name" value="$@name">
>             </xsl:when>
>             </xsl:choose>
>            </go>
>          </do>
>         <xsl:apply-templates select="*"/>
>        </xsl:template>
>
> Though i should check in input[@type='radio'] that name of the
> preceding sibling is same or not because in type radio name is
> same for all.so it should come only once .
> But this is not working even after removing the when condition  of
> input type radio and simply using type check box only .
> It is giving error .
> What is wrong in it and what should be the correct way.
> Itried various combinations even removing for-each loop and giving
> only one input type =checkbox in input but it is not working .
> The rest of style sheet working .
> if i use only
>
>    <xsl:template match="form">
>           <p><xsl:apply-templates select="*"/>
>        </xsl:template>
> It is working but as obvious not creating any post field which is
> required for form handling.
> Need help.
> Alexek
>
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>


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