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RE: selecting all nodes which contains similar names
- From: =?utf-8?B?IkJyYXVtw7xsbGVyLCBIYW5zIg==?= <h dot braumueller at hanseorga dot de>
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 26 Jul 2002 13:11:20 +0200
- Subject: RE: [xsl] selecting all nodes which contains similar names
- Reply-to: xsl-list at lists dot mulberrytech dot com
Sorry
it have a syntax error,
it´s function very well:
<xsl:for-each select="node()[contains(name(), 'umszweck')]">
Hans
> Hi,
>
> i know this is a FAQ, but i cannot find it with google and in
> the archive.
>
> I want to extract with a shortest statement all nodes which
> begins with the
> same characters in the element .
>
> xml snippet
> ----
>
> <row>
> ...
> <umszweck1>UMSZWECK1</umszweck1>
> <umszweck2>UMSZWECK2</umszweck2>
> <umszweck3>UMSZWECK3</umszweck3>
> <umszweck4>UMSZWECK4</umszweck4>
> <umszweck5>UMSZWECK5</umszweck5>
> <umszweck6></umszweck6>
> <umszweck7>UMSZWECK7</umszweck7>
> <umszweck8>UMSZWECK8</umszweck8>
> <umszweck9>UMSZWECK9</umszweck9>
> <umszweck10></umszweck10>
> <umszweck11>UMSZWECK11</umszweck11>
> <umszweck12>UMSZWECK12</umszweck12>
> <umszweck13>UMSZWECK13</umszweck13>
> <umszweck14>UMSZWECK14</umszweck14>
> etc
> ...
> </row>
>
> xsl try
> ----
> <xsl:-for each select="node()[contains(name(),'umszweck')]">
> <xsl:value-of select="." />
> </xsl:for-each>
>
> It´s not function!
>
> Must i do a when=test()?
> It is possible instead using a template?
> Anybody can forward me a code snippet?
> Excuse my still a beginner question!
>
> Have a nice weekend!
>
> Thanks,
>
> Hans Braumüller
> -- + --
> Networking Artist
> http://crosses.net
> http://kunstserie.com
>
>
>
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