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RE: transformation does happen after copy-of?
- From: Américo Albuquerque <aalbuquerque at viseu dot ipiaget dot pt>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Tue, 23 Jul 2002 11:53:41 +0100
- Subject: RE: [xsl] transformation does happen after copy-of?
- Organization: IPiaget - DT Viseu
- Reply-to: xsl-list at lists dot mulberrytech dot com
So why does the values of the attributes get print out??
-----Original Message-----
From: owner-xsl-list@lists.mulberrytech.com
[mailto:owner-xsl-list@lists.mulberrytech.com] On Behalf Of David
Carlisle
Sent: Tuesday, July 23, 2002 11:25 AM
To: xsl-list@lists.mulberrytech.com
Subject: Re: [xsl] transformation does happen after copy-of?
> I supose that the attribute nodes does't get selected in the node()
> function
node() isn't a function, it is a node test, like text(). attribute nodes
are matched by node() but
select="node()" is short for
select="child::node()"
and attribute nodes are not child nodes of any node.
> so, when you do a match="node()" you are selecting all nodes except
> attribute nodes, b
no node() does match attribute nodes.
> but these also have text nodes (that contain
> there values) and these are selected by the match="node()"
attribute nodes do not have any children. The value of an attribute i
not a text node.
david
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