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Adding a node to an existing node set
- From: Tom Zwick <sammy4352 at yahoo dot com>
- To: xsl <xsl-list at lists dot mulberrytech dot com>
- Date: Mon, 22 Jul 2002 14:44:10 -0700 (PDT)
- Subject: [xsl] Adding a node to an existing node set
- Reply-to: xsl-list at lists dot mulberrytech dot com
Say the XPath expression ="/parent/child" returns all
children, how can I add a new child element and have
the resulting node set assigned to a variable.
I tried
<xsl:variable name="newTree">
<xsl:copy-of select="/parent/child"/>
<child age="1">foo</child>
</xsl:variable>
However there seems to be a difference between
<xsl:variable name="newTree" select="/parent/child"/>
and
<xsl:variable name="newTree">
<xsl:copy-of select="/parent/child"/>
</xsl:variable>
Amont other things, the attributes seem to have
disappeared.
Can someone explain the difference between the two?
Also when I try
<xsl:variable name="newTree">
<xsl:for-each select="/parent/child">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
Saxon complains saying : "Cannot write an attribute
when there is no open start tag"
Thanks,
Tom
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