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Re: Identity Transform and Default Templates, I think...
- From: David Carlisle <davidc at nag dot co dot uk>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Wed, 19 Jun 2002 09:50:29 +0100
- Subject: Re: [xsl] Identity Transform and Default Templates, I think...
- References: <63C4AD0365821F4291ACF76C0672FA3506EEA6@piper6.piper-group.int>
- Reply-to: xsl-list at lists dot mulberrytech dot com
As far as I know, these two are equivalent:
in full:
<node>
<xsl:attribute name="id">
<xsl:value-of select="node"/>
</xsl:attribute>
</node>
avt:
<node id="{node}"/>
oops yes I was thinking about the version i gave in my reply not this
version, sorry.
The only way around producing id="" (if node is empty/not there) is to
use:
<node>
<xsl:if test="node">
<xsl:attribute name="id">
<xsl:value-of select="node"/>
</xsl:attribute>
</xsl:if>
</node>
Or simpler in the case of just copying, which is what i gave in my first
reply and was thinking about when I gave the incorrect response above:
<node>
<xsl:copy-of select="@id"/>
</node>
David
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