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RE: pattern matching in xslt


At 03:01 PM 4/23/2002, you wrote:
>Regarding exslt, I don't think I can implement anything but the default
>Xalan, IBM XML for Java packages. Thanks just the same!

   The stuff at exslt.org are ordinary templates.  I assume that Xalan can 
execute an XSL template.

   [time passes]

   I just completed your request; here is your XSL stylesheet.  You will 
need to modify the path to reflect Xalan's namespace and (I assume it has 
this) its node-set extension function.  I used MSXSL so you can delete 
those references.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
xmlns:msxsl="urn:schemas-microsoft-com:xslt" 
xmlns:str="http://www.exslt.org/str"; extension-element-prefixes="msxsl str">
   <xsl:import href="strings.xsl" xmlns="http://www.exslt.org/str"/>
   <xsl:template match="/">
     <xsl:apply-templates select="*"/>
   </xsl:template>
   <xsl:template match="description">
     <xsl:element name="result">
       <xsl:variable name="tokens">
         <xsl:call-template name="str:tokenize">
           <xsl:with-param name="string" select="."/>
         </xsl:call-template>
       </xsl:variable>
       <xsl:variable name="token-node-set" select="msxsl:node-set($tokens)"/>
       <xsl:for-each select="$token-node-set/*[. != '..']">
         <xsl:value-of select="."/>
         <xsl:if test="position() != last()">
           <xsl:value-of select="' '"/>
         </xsl:if>
       </xsl:for-each>
     </xsl:element>
   </xsl:template>
</xsl:stylesheet>


Greg Faron
Integre Technical Publishing Co.



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