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cross-reference & xsl:sort - MSXML3 vs MSXML4
- From: David Chryst <dchryst at yahoo dot com>
- To: XSL-List at lists dot mulberrytech dot com
- Date: Mon, 15 Apr 2002 15:44:15 -0700 (PDT)
- Subject: [xsl] cross-reference & xsl:sort - MSXML3 vs MSXML4
- Reply-to: xsl-list at lists dot mulberrytech dot com
I want to pass in a collection/@name and get a list of
all the corresponding part elements (cross refence).
Then I want to sort the data first by part/@type, then
by part/@name. I lifted the sample xml from a similar
note posted to this list in October 2001. That email
is duplicated at the bootom. I never did see that
problem answered.
First, I added a little more sample data (groupC) to
the xml:
<large-collection>
<part id="1" type="type-a" name="name-a"/>
<part id="2" type="type-a" name="name-b"/>
<part id="3" type="type-b" name="name-c"/>
<part id="4" type="type-d" name="name-d"/>
<part id="5" type="type-b" name="name-e"/>
<part id="6" type="type-c" name="name-f"/>
<part id="7" type="type-d" name="name-g"/>
<part id="8" type="type-b" name="name-h"/>
<part id="9" type="type-c" name="name-i"/>
...
<collection name = "groupA">
<ref refid="1"/>
<ref refid="3"/>
</collection>
<collection name = "groupB">
<ref refid="3"/>
<ref refid="4"/>
</collection>
<collection name = "groupC">
<ref refid="1"/>
<ref refid="2"/>
<ref refid="3"/>
<ref refid="4"/>
<ref refid="5"/>
<ref refid="6"/>
<ref refid="7"/>
<ref refid="8"/>
<ref refid="9"/>
</collection>
</large-collection>
here's my XSL:
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="html" />
<xsl:variable name="MyGroup">groupC</xsl:variable>
<xsl:template match="/large-collection/collection">
<xsl:if test="./@name=$MyGroup">
<xsl:for-each select="ref">
<xsl:sort select="/large-collection/part[@id =
(current())/@refid]/@type" order="ascending"/>
<xsl:sort select="/large-collection/part[@id =
(current())/@refid]/@name" order="ascending"/>
type: <xsl:value-of
select="concat(/large-collection/part[@id =
(current())/@refid]/@type, ' name: ',
/large-collection/part[@id =
(current())/@refid]/@name, ' id: ',
/large-collection/part[@id =
(current())/@refid]/@id)"/>
</xsl:for-each>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
I ran this XSLT script using MSXML3 DOM and Processor
and got this output:
type: type-a name: name-a id: 1
type: type-a name: name-b id: 2
type: type-b name: name-c id: 3
type: type-b name: name-e id: 5
type: type-b name: name-h id: 8
type: type-c name: name-f id: 6
type: type-c name: name-i id: 9
type: type-d name: name-d id: 4
type: type-d name: name-g id: 7
Note the output is sorted correctly (By type, then by
name). Now look at the output I get running that same
script using MSXML4:
type: type-a name: name-a id: 1
type: type-a name: name-b id: 2
type: type-b name: name-c id: 3
type: type-d name: name-d id: 4
type: type-b name: name-e id: 5
type: type-c name: name-f id: 6
type: type-d name: name-g id: 7
type: type-b name: name-h id: 8
type: type-c name: name-i id: 9
This data is in document order! What gives?
David
>Hi, following is an example of an xml structure that
I
>require grouped through the use of cross references
>based on a parameterised filter value. The xml
>structure is fairly large so the use of keys to
lookup
>the 'part' element is highly desirable.
>I am currently using xsl:param to define a filter
>value for 'collection@name' having got that I need to
>return a result set that for all the 'parts' referred
>to by 'ref@refid' references in the 'collection'
>grouped by 'part@type', sorted with in each group by
>'part@name'. It would also be desirable to have the
>result set assigned to an xsl:variable.
<large-collection>
<part id="1" type="type-a" name="name-a"/>
<part id="2" type="type-a" name="name-b"/>
<part id="3" type="type-b" name="name-c"/>
<part id="4" type="type-d" name="name-d"/>
<part id="5" type="type-b" name="name-e"/>
<part id="6" type="type-c" name="name-f"/>
<part id="7" type="type-d" name="name-g"/>
<part id="8" type="type-b" name="name-h"/>
<part id="9" type="type-c" name="name-i"/>
...
<collection name = "groupA">
<ref refid="1"/>
<ref refid="3"/>
</collection>
<collection name = "groupB">
<ref refid="3"/>
<ref refid="4"/>
</collection>
</large-collection>
>Cheers
>Tom Hall
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