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XSLT Java Extensions
- From: "Garvin Franco" <garvin_franco at hotmail dot com>
- To: XSL-List at lists dot mulberrytech dot com
- Date: Sun, 14 Apr 2002 19:28:15 -0400
- Subject: [xsl] XSLT Java Extensions
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hello ladies/gents, I am trying to use extensions in XSLT to get the current
date/time for textual output, but I don't know how to retrieve specific data
from the object returned.
Below is a sample of the xsl file that makes the extension call:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java">
..
..
<!-- I am making this call inside the template: -->
<xsl:variable name="tmp" select="java:java.util.Calendar.new()"/>
<xsl:value-of select="$tmp" />
..
</xsl:stylesheet>
The problem with this is that, when I instantiate the Calendar object it
returns a GregorianCalendar object with a great deal of information that I
don't want. So when I write it to output, the entire object is returned.
All I need on the text output is YYYYMMDDHHMMSS. These details are stored in
the attributes of the Class.
YEAR MONTH DAY_OF_MONTH HOUR_OF_DAY MINUTE SECOND
I tried using
"<xsl:value-of select="java:java.util.Calendar.get(YEAR)" />" etc., but I
got error messages when the processor tried to process these lines.
Can someone give me some pointers on this?
Thanks
Garvin
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