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How to pass search path as variable and get back node list.
- From: "Andrew Kerns" <akerns at ers dot usda dot gov>
- To: <XSL-List at lists dot mulberrytech dot com>
- Date: Wed, 27 Mar 2002 15:45:58 -0500
- Subject: [xsl] How to pass search path as variable and get back node list.
- Reply-to: xsl-list at lists dot mulberrytech dot com
I have searched FAQ section and can not find answer.
I know it must be there but I can not find it.
Please excuse the redundant question.
Can't figure out how to pass search path as variable and get back node
list.
I get back search string value instead of node list.
<xsl:param name="DATA_REQUEST_NAME"/>
<xsl:variable name="ftype_search"
select="concat('//JOB_REQUEST/DATA_REQUEST[@NAME=',$DATA_REQUEST_NAME,']/FILE_TYPE')"/>
<xsl:variable name="chosen_ftype" select="$ftype_search"/>
xsl:value-of select="$chosen_ftype"/>
Returns
//JOB_REQUEST/DATA_REQUEST[@NAME=DATAREQUEST4]/FILE_TYPE
How can I get the node list returned instead of the string?
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