[xsl] suppressing default template rules

[Aseef Jamaluddin <j_aseef at yahoo dot com>]

Hi All,
Please find below the xml and xsl files i am working
on. What i am trying to do is print the  firstname and
secondname when the employee element is encountered.
But now i am getting two sets of values printed. I
assume that the second set is due to the
built(default) in template rule for matching all
text() nodes. If so what could be the way out.


<?xml version="1.0" ?>
<custdet>
<employee>
</employee>
	<firstname>first</firstname>
	<lastname>last</lastname>
</custdet>


<?xml version="1.0"?> 
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">

<xsl:template match="firstname">
<b>
<xsl:value-of select="."/>
</b>
</xsl:template>

<xsl:template match="lastname">
<i><b>
<xsl:value-of select="."/>
</b></i>
</xsl:template>

<xsl:template match="employee">
<xsl:apply-templates select="//firstname"/>
<xsl:apply-templates select="//lastname"/>
</xsl:template>

</xsl:stylesheet>

Thanks in advance
aseef.j

__________________________________________________
Do You Yahoo!?
Yahoo! Movies - coverage of the 74th Academy Awards®
http://movies.yahoo.com/

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list