RE: [xsl] xsl:sort by element name

["Michael Kay" <michael dot h dot kay at ntlworld dot com>]

select="/*" will select a single element, the <LLL>, so there's not much
point sorting it.

But in your sample, all the elements at the next level have the same name,
so it's hard to see what you're getting at.

Michael Kay
Software AG
home: Michael.H.Kay@ntlworld.com
work: Michael.Kay@softwareag.com

> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of
> Mike Ferrando
> Sent: 13 March 2002 15:58
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] xsl:sort by element name
>
>
> Dear List,
> I am trying to sort my output nodes based on their element name.
>
> Could someone give me a hint on this one?
>
> Mike F.
>
>
> XML:
> <LLL>
>   <C1012>...C-data...</C1012>
>   <C1012>...A-data...</C1012>
>   <C1012>...B-data...</C1012>
> </LLL>
>
> Output should be:
> <LLL>
>   <C1012>...A-data...</C1012>
>   <CC1012>...B-data...</CC1012>
>   <CCC1012>...C-data...</CCC1012>
> </LLL>
>
>
> XSL:
> <xsl:template select="/">
>   <xsl:for-each select="/*">
>     <xsl:sort select="name()"/>
>       <xsl:apply-templates select="C1012"/>
>   </xsl:for-each>
> </xsl:template>
>
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