Re: [xsl] sort

[David Carlisle <davidc at nag dot co dot uk>]

> but now i would like to sort the xmlstring on "root.person.supelogin.login"

well guessing whatyou mean by "." You coukd do

<xsl:sort select="root/person/supelogin/login"/>

If you want to pass the name of the sort element as a param, and only
want to use the eleemnts in supelogin you can do

<xsl:sort select="root/person/supelogin/*[name()=$$sortering]"/>

If you want to supply the full path as a param you are in the territory
of using saxon:evaluate()

David

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