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How to get a value from other node
- From: Aleksander Bracko <aleksander dot bracko at hermes dot si>
- To: "'XSL-List at lists dot mulberrytech dot com'" <XSL-List at lists dot mulberrytech dot com>
- Date: Thu, 31 Jan 2002 08:55:44 +0100
- Subject: [xsl] How to get a value from other node
- Reply-to: xsl-list at lists dot mulberrytech dot com
I have following XML:
<MyXml>
<header>
<location>
Home
</location>
</header>
<content>
<city name = "city1">
<address>
Address1
</address>
</city>
<city name = "city2">
<address>
Address2
</address>
</city>
</content>
</MyXml>
My XSL looks like this:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="header">
<MyHome>
<xsl:value-of select="location"/> <------ After this I
want to insert another value from other node (address)
</MyHome>
<xsl:apply-templates />
</xsl:template>
</xsl:stylesheet>
And now my problem is:
I would like to insert another value, but from other node. I thought that i
could use a line like this one, but it doesn't work
<xsl:if test="../content/city@name[.='city2']">
<xsl:value-of select="../content/city/address" />
</xsl:if>
If u could please help me out.
Thanx, Alex
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