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Re: Date-Format: How can i use this??
Hi Asim,
you can use the substring()-function:
<xsl:template match="OBX">
<xsl:text>Datum: </xsl:text>
<xsl:value-of select="substring(@ObservationDT,9,2)"/>
<xsl:text>.</xsl:text>
<xsl:value-of select="substring(@ObservationDT,6,2)"/>
<xsl:text>.</xsl:text>
<xsl:value-of select="substring(@ObservationDT,1,2)"/>
<xsl:text>
Uhrzeit: </xsl:text>
<xsl:value-of select="substring(@ObservationDT,12,5)"/>
</xsl:template>
Maybe you have to change the exact numbers, but that's the way.
Your second question: <xsl:value-of select="translate(@Unit_ID, 'U', 'L')"/>
Regards,
Joerg
> Hi,
>
> i have this XML:
>
> <tdPAVSelection>
> <OBX ObservationDT="2001-11-04T08:00:00" Observation_ID="2157-6"
> ValueType_ID="NM" Value="105" Unit_ID="U/L" AbnormFlag_ID="H"
> ResultState_ID="F" FootnoteID="29"/>
> </tdPAVSelection>
>
> But i need this Result for ObservationDT:
>
> Datum : 04.11.2001
> Uhrzeit : 08:00
>
> My second question:
>
> I have in Tag Unit_ID = "U/L". But i want Replace U with ?. So i have
> ?/L instead of U/L.
>
> Thanks for Help for a newbie
>
> Asim
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