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RE: FW: Path Reversal



Hi,

I know there have been a few goes at this, but I thought I would do one as
well :)

This stylesheet recursively extracts each word of the path (the bits in
between the slashes) and then when its at the final word, selects the
content of the node using '//'.

It may help, i dunno....

==stylesheet==
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">
<xsl:call-template name="text_wrapper">
   <xsl:with-param name="Text" select="'/funstuff/jokes/veryfunnyjoke'"/>
</xsl:call-template>
</xsl:template>

<xsl:template name="text_wrapper">
<xsl:param name="Text"/>
<xsl:choose>
    <xsl:when test="contains($Text,'/')">
      <xsl:call-template name="text_wrapper">
        <xsl:with-param name="Text" select="substring-after($Text,'/')"/>
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="//node()[@name=$Text]"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

</xsl:stylesheet>

==input==
<?xml version="1.0"?>
<root>
<node name="funstuff">
   <node name="jokes">
     <node name="veryfunnyjoke">the joke</node>
   </node>
</node>
</root>

==output==
<?xml version="1.0" encoding="utf-8"?>the joke



cheers

andrew

===


-----Original Message-----
From: owner-xsl-list@lists.mulberrytech.com
[mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Alek Andreev
Sent: Monday, January 28, 2002 2:18 PM
To: xsl-list@lists.mulberrytech.com
Subject: [xsl] FW: Path Reversal


Hi!

Suppose I have the following piece of XML:

<node name="funstuff">
  <node name="jokes">
    <node name="veryfunnyjoke"/>
  </node>
</node>

I have a path (as a string) which is composed of the @names of the
nodes. It looks like /funstuff/jokes/veryfunnyjoke. How can I write a
template (or an EXSLT function) that returns the node the path points to
(e.g. veryfunnyjoke)?


Regards,
Alek Andreev
alek@post.com



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