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RE: how to rearrange nodes based on a dependency graph?
- From: "Chris Bayes" <chris at bayes dot co dot uk>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Thu, 20 Dec 2001 21:26:05 -0000
- Subject: RE: [xsl] how to rearrange nodes based on a dependency graph?
- Reply-to: xsl-list at lists dot mulberrytech dot com
What about
<xsl:for-each select='*[not(@requires)]'>
<xsl:call-template name='copy-stuff'/>
</xsl:for-each>
Ciao Chris
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