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RE: for-each order
- From: "Long Zhao" <LZhao at firstgenetic dot net>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 14 Dec 2001 11:34:19 -0600
- Subject: RE: [xsl] for-each order
- Reply-to: xsl-list at lists dot mulberrytech dot com
how about this
<xsl:variable name="position">
<xsl:for-each select="$path">
<xsl:value-of select="concat(@value, position)"/>,
</xsl:for-each>
</xsl:variable>
Long
-----Original Message-----
From: Charly [mailto:cohana@investacorp.com]
Sent: Friday, December 14, 2001 2:35 PM
To: xsl-list@lists.mulberrytech.com
Subject: [xsl] for-each order
Hello,
Is there a way to do <xsl:for-each ..... and looping backwards.
My XML looks like
<histo>
<bar value="60" legend="Jan" />
<bar value="77" legend="Feb" />
<bar value="53" legend="Mar" />
<bar value="14" legend="Apr" />
</histo>
and I want to store 14,53,77,60 in a variable .
<xsl:variable name="position">
<xsl:for-each select="$path">
<xsl:value-of select="@value"/>,
</xsl:for-each>
</xsl:variable>
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