Re: [xsl] Confusion over /, //, current() and .

["Dennis Campillo" <dcampillo at msn dot com>]

>I thought "current()" and "."
>gave you the same thing.
>
     This is pretty much the only information I can find regarding the 
current() function. It does show however that current() is not always the 
same as "."

(from the W3C XSLT spec)
The current function returns a node-set that has the current node as its 
only member. For an outermost expression (an expression not occurring within 
another expression), the current node is always the same as the context 
node. Thus,

<xsl:value-of select="current()"/>

means the same as

<xsl:value-of select="."/>

However, within square brackets the current node is usually different from 
the context node. For example,

<xsl:apply-templates select="//glossary/item[@name=current()/@ref]"/>

will process all item elements that have a glossary parent element and that 
have a name attribute with value equal to the value of the current node's 
ref attribute. This is different from

<xsl:apply-templates select="//glossary/item[@name=./@ref]"/>

which means the same as

<xsl:apply-templates select="//glossary/item[@name=@ref]"/>





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