This is the mail archive of the
xsl-list@mulberrytech.com
mailing list .
Re: Beginner's question
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Beginner's question
- From: Jörg Heinicke <joerg dot heinicke at gmx dot de>
- Date: Thu, 04 Oct 2001 18:12:30 +0200
- References: <5.1.0.14.2.20011004162610.00b1ed60@pop.compuserve.com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
<xsl:stylesheet ...>
<!-- parameterized stylesheet, getting param from outside -->
<xsl:param name="desired-id"/>
<xsl:template match="root-element">
<xsl:copy-of select="descendant::site[uid = $desired-id]"/>
</xsl:template>
</xsl:stylesheet>
Joerg
J S Publications wrote:
> Hi
>
> Here is a simple question from an absolute beginner!
>
> Suppose I have an XML document with a complex DTD. The DTD contains an
> element deep in the hierarchy called <site>. A <site> contains within it
> an element called <uid> that uniquely identifies the <site>.
>
> How would I transform the XML doc to another XML doc that contained just
> the <site> element with a given <uid> (the output to include all child
> elements of site)?
>
> I said it was a simple question!
>
> Chris
--
System Development
VIRBUS AG
Fon +49(0)341-979-7435
Fax +49(0)341-979-7409
joerg.heinicke@virbus.de
www.virbus.de
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list