Re: [xsl] questions.

[Jörg Heinicke <joerg dot heinicke at gmx dot de>]

Hi Mihir,

I think here you have a problem of unserstanding XSL. You don't modify the 
original XML-tree, you create a new one. This is important!! If you really 
want to "translate" <b> to <x>, you don't need to "delete" <b>, you only 
need to add <x>.

An example stylesheet:

<xsl:template match="a|c">
   <xsl:copy>
     <xsl:apply-templates/>
   </xsl:copy>
</xsl:template>

<xsl:template match="b">
   <x>
     <xsl:apply-templates/>
     <m></m>
     <n></n>
   </x>
</xsl:template>

Hope this helps,

Joerg


Mihir D. Gore wrote:

> but if want to replace node b with node z ie
> 
> <a>
> 	<b>
> 		<c></c>
> 	</b>
> </a>
> 
> is changed to
> <a>
> 	<x>
> 		<c></c>
> 		<m></m>
> 		<n></n>
> 	<x>
> </a>
> 
> I can achive this by simply deleting node b and its chilren and adding node
> x.
> Is there any other way around this?
> 
> mihir
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Manu KY
> Sent: Thursday, October 04, 2001 2:09 PM
> To: xsl-list@lists.mulberrytech.com
> Subject: Re: [xsl] questions.
> 
> 
> Hi,
> write xsl:template match = "b"
> 
> Manu
> 
>>hi,
>>I have a xml file in the form
>>
>><a>
>>        <b>
>>                <c></c>
>>        </b>
>></a>
>>
>>I want to add two more children to node b say  m and n so that the
>>
> resultant
> 
>>xml looks like this.....
>>
>><a>
>>        <b>
>>                <c></c>
>>                <m></m>
>>                <n></n>
>>        </b>
>></a>
>>
>>BUT in the xsl file in want to specify the path with respect to node b.
>>How do i do it?
>>mihir


-- 

System Development
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