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Re: questions?
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] questions?
- From: "Christopher R. Maden" <crism at maden dot org>
- Date: Mon, 17 Sep 2001 21:58:25 -0700
- Reply-To: xsl-list at lists dot mulberrytech dot com
At 21:29 17-09-2001, Mihir D. Gore wrote:
>If i have a operation like "insert node n as the i th child of node p" ,
>what will be the the xsl?
To repeat a FGA[*], XSLT can't change the source. It reads the source and
writes output.
>for example
><book>
> <author>P.G.Wodehouse</author>
> <name>Good Morning Jeeves</name>
> <price>20</price>
></book>
>
>if i add the node <review></review> as the 3rd child of book then the xsl
>will be
>
><book>
> <author>P.G.Wodehouse</author>
> <name>Good Morning Jeeves</name>
> <review>Some comments here</review>
> <price>20</price>
></book>
What you want to do is copy the book, with the review added. You could do
this by starting with the identity transform (see the XSLT Recommendation)
and adding
<xsl:template match="book">
<xsl:copy select=".">
<xsl:apply-templates select="*[position() < 3]"/>
<review>Some comments here</review>
<xsl:apply-templates select="*[position() >= 3]"/>
</xsl:copy>
</xsl:template>
-Chris
[*] Frequently given answer.
--
Christopher R. Maden, Principal Consultant, HMM Consulting Int'l, Inc.
DTDs/schemas - conversion - ebooks - publishing - Web - B2B - training
<URL: http://www.hmmci.com/ > <URL: http://crism.maden.org/consulting/ >
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