Re: [xsl] getting XSL to output XSL...

[Jeni Tennison <mail at jenitennison dot com>]

Hi Rafael,

> How do I write a stylesheet that generates another stylesheet? Will
> XSLT processors be smart enough to note that:
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>   xmlns:xslout="http://www.w3.org/1999/XSL/Transform";
>   version="1.0"/>
>
> the <xslout:.../> tags are not supposed to be processed? I've
> thought of slightly modifying the namespace URI for the new
> stylesheet but I want to avoid making manual changes to the result
> if at all possible.

As far as XSLT processors (and any namespace-aware application) is
concerned, the two prefixes 'xsl' and 'xslout' mean exactly the same
thing and can be used interchangeably. But you're part way there.
Change the xslout namespace a little so that it's not the XSLT
namespace, e.g. to:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                xmlns:xslout="http://www.w3.org/1999/XSL/TransformAlias";
                version="1.0">
...
</xsl:stylesheet>

Then use the xsl:namespace-alias element to tell the processor that
elements and attributes that you generate in the xslout namespace
should be output in the XSLT namespace, with:

<xsl:namespace-alias stylesheet-prefix="xslout" result-prefix="xsl" />

You can then use xslout as the prefix on the elements that you want to
output, and xsl as the prefix on the elements that you want to act as
instructions.

I hope that helps,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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