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RE: count all the following nodes of a perticular parent
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] count all the following nodes of a perticular parent
- From: "Ben Robb" <b dot robb at cscape dot com>
- Date: Thu, 28 Jun 2001 11:04:33 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
Try count() ;)
count(following::*)
> -----Original Message-----
> From: Jayaranga Subasinghe [mailto:jayarangas@eurocenter.lk]
> Sent: 28 June 2001 10:52
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] count all the following nodes of a perticular parent
>
>
> hello,
> i want to count all the following nodes from the current node
> of the same
> parent
> can anybody give me a way to do this?
> thank you
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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