RE: [xsl] position() of a current node

["Michael Kay" <mhkay at iclway dot co dot uk>]

I'm confused too, because your sections aren't part of a chapter, they are
part of a part.

Getting position() values of 2,4,6 or 1,3,5 is usually because you are
processing the whitespace nodes between elements as well as the elements.
This doesn't seem to be the case in your example.

Please post a complete stylesheet and tell us which processor you're using.

Mike Kay

> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of
> Daniel Bauke
> Sent: 15 June 2001 13:41
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] position() of a current node
>
>
> i've checked a faq, but i'm still confused.
> i've got:
>
> xsl:
> <xsl:template match="chapter">
>    <xsl:for-each select="section">
>       <xsl:value-of select="position()"/>
>    </xsl:for-each>
>    <xsl:apply-templates select="section"/>
> </xsl:template>
>
> <xsl:template match="section">
>    <xsl:value-of select="position()">
> </xsl:template>
>
> and an xml like that:
> <document>
>    <part name="one">
>       <section name="1">blah</section>
>       <section name="2">bleh</section>
>       <section name="3">blah</section>
>    </part>
>    <part name="two">
>       <section name="1">blah</section>
>       <section name="2">bleh</section>
>       <section name="3">blah</section>
>    </part>
> </document>
>
> and i'm wondering how to return real position of each section
> (now i'm geting 1,3,5)
>
> --
> Daniel `bonkey' Bauke; http://www.oho.pl/~bonkey/;
> {happiness=bike&&unix;}
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


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