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- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] xsl:copy-of
- From: "Michael Kay" <mhkay at iclway dot co dot uk>
- Date: Mon, 21 May 2001 11:33:26 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
> This does the job fine. Now I want to make my XSLT more
> generic so I don't
> have to specifically say that the "<BODY>" is a CDATA
> section. Basically I
> want an exact copy of the original document whatever the
> original document
> may be.
If you're saying, you want CDATA sections in the input to result in CDATA
sections in the output, you can't: the XML parser throws away the
information as to whether the input was CDATA before the XSLT transformer
gets to see it.
This is because in the XPath data model
are defined to be precisely equivalent: they are simply different ways of
writing the same thing.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list