Re: [xsl] soft returns/wrap not displaying the way I want

[David Carlisle <davidc at nag dot co dot uk>]

> 	2. display hard returns.

You need to define what a hard return is (There is no such concept in
HTML). I think you mean a <br/> element.

In which case take the replace every newline character by a
<br/> element.
This is a FAQ and there's code to do this replacement at the faq for
this list at

http://www.dpawson.co.uk/xsl/break.html


> I would somehow nest the xsl select statement in a table
in a table if you want or just a div with a specified width.


>  and have any line break
> 	characters (&#10) go to <br/> (taking care of the hard
> 	returns/enter

yes see the above page

so putting it together you just want
<xsl:template match="xxxx">

      <div width="...">
      <xsl:call-template name="substitute">
         <xsl:with-param name="string" select="." />
      </xsl:call-template>
      </div>
</xsl:template>



where the substitute template is defined in the page quoted above.

David

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