RE: [xsl] Ampersand for URLs

[Robert Seber <robert dot seber at netdecisions dot co dot uk>]

Which platform and version of Netscape?

This link works fine in Netscape 4.08 and Netscape 6.0 for PC:

<a
href="http://www.thefirstresort.com/dreamtime/resortguide/resortguide.asp?lo
cation_code=EU_02_03_04&amp;Section=HolidayFinder">Go!</a>

As you can see it uses an &amp;



> -----Original Message-----
> From: Daniel Newman [mailto:daniel.newman@bis-web.net]
> Sent: Friday, April 20, 2001 10:17 AM
> To: xsl-list@lists.mulberrytech.com
> Subject: RE: [xsl] Ampersand for URLs
> 
> 
> Netscape does NOT like &amp; in the href, it results in a 401 
> error. Bit of
> a pain, but there you go.
> 
> 
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of 
> Robert Seber
> Sent: 20 April 2001 10:01
> To: xsl-list@lists.mulberrytech.com
> Subject: RE: [xsl] Ampersand for URLs
> 
> 
> In my experience all browsers will understand both & and 
> &amp; in hrefs.  In
> fact, using &amp; is safer as IE4 sometimes sees &something 
> in a URL as a
> character entity and translates it, causing all sorts of problems.
> 
> 
> > -----Original Message-----
> > From: P.Vogt@mainwork.com [mailto:P.Vogt@mainwork.com]
> > Sent: Friday, April 20, 2001 9:36 AM
> > To: xsl-list@lists.mulberrytech.com
> > Subject: [xsl] Ampersand for URLs
> >
> >
> > Hello!
> >
> >   Perhaps someone on this list can help me with a little problem:
> >
> > I want to transform an xsl to html which contains a url. This
> > url has an
> > ampersand, which seperate cgi-parameters. My problem is, that
> > the xalan
> > processor translates the & in &amp; (which should be ok
> > refering to the
> > xslt-reference and the faq).
> >
> > Example:
> >
> > Xsl:
> > <img><xsl:attribute
> > name="src">http://www.thehost.com/thescript?param=<xsl:value-of
> > select="number"/><![CDATA[&]]>img=5</xsl:attribute></img>
> >
> > results in
> >
> > HTML:
> >
> > <img
> > src="http://www.thehost.com/thescript?param=15&amp;anotherparam=5";>
> >
> > But I need:
> >
> > <img src="http://www.thehost.com/thescript?param=15&anotherparam=5";>
> >
> > Is there a workaround to get this url?
> >
> > I use:
> >
> > <xsl:stylesheet version="1.0"
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> >   <xsl:output doctype-public="-//W3C/DTD HTML 4.0 Transitional//EN"
> > doctype-system="http://www.w3c.org/TR/REC-html40/loose.dtd";
> > method="html"
> > version="1.0" indent="yes" encoding="ISO-8859-1"
> > media-type="text/html"/>
> >
> > in the XSL, if that is of any help.
> >
> >   Philipp
> >
> > --
> > Philipp Vogt
> > Web-Entwickler/Programmierer/Member of visionLab
> > mainwork information technology AG
> > Höchstädtplatz 3 / 202, 1200 Wien
> > E-Mail: p.vogt@mainwork.com
> > Tel: +43 1 796 70 60
> > Fax: +43 1 796 70 60 - 60
> > Mobil: +43 699 1 946 95 24
> >
> >  XSL-List info and archive:  
> http://www.mulberrytech.com/xsl/xsl-list
> >
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

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