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Jumping out a loop
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl]Jumping out a loop
- From: "Tanzila Mohammad" <tmohammad at entier-solutions dot com>
- Date: Wed, 18 Apr 2001 11:03:15 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
I have the following loop:
<xsl:for-each select="Grasslands/*[position()>3 and text()]">
<h3><font color="#00007f"><i><xsl:value-of
select="name()"/></i></font></h3>
<p><font color="#008000"><xsl:value-of select="."/></font></p>
</xsl:for-each>
I want to jump out the loop at two children and perform a different function
for them:
For the Links of Genus child:
<h3><a NAME="Label0045"></a><font color="#00007F"><i>Links for the
genus:</i></font></h3>
<ul>
<xsl:for-each select="Grasslands/LinksForTheGenus/Link">
<li><font color="#008000"> <xsl:value-of
select="Address"/>;
<xsl:value-of select="Name"/> </font></li>
</xsl:for-each>
</ul>
For The References child:
<h3><a NAME="Label0045"></a><font
color="#00007F"><i>References:</i></font></h3>
<xsl:for-each select="Grasslands/References/Ref">
<font color="#008000"> <xsl:value-of select="Name"/>

<xsl:value-of select="Year"/>;
</font>
</xsl:for-each>
References and Links for Genus are slightly different than all children of
Grasslands, I figure I need some sort of 'if' statement maybe:
<xsl:if test="Grasslands[LinksForTheGenus]"> do process
<xsl:if test="Grasslands[References]"> do process
Any suggestions.
Tanz
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