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Node comparison
- To: xsl-list at lists dot mulberrytech dot com
- Subject: [xsl] Node comparison
- From: Kevin_Gutch at mapinfo dot com
- Date: Sat, 14 Apr 2001 19:12:16 -0400
- Reply-To: xsl-list at lists dot mulberrytech dot com
Having two different XML's joined on an entity reference I need to
compare values underneath two different parent nodes without having to use
a $Position Variable. The reason being is that I may not have a one to one
relationship. So
with an example below I would like to use my XSLT to base the values of
Parent 2 on the like values in Parent 1.
<?xml version="1.0" encoding="UTF-8"?>
<Parent 1>
<Value 1>1</Value 1>
<Value 2>0</Value 2>
<Value 3>1</Value 3>
<Value 4>0</Value 4>
</Parent 1>
<Parent 2>
<Value 1> </Value 1>
<Value 2> </Value 2>
<Value 2> </Value 2>
<Value 3> </Value 3>
<Value 4> </Value 4>
</Parent 2>
I would like the following results:
<Parent 1>
<Value 1>1</Value 1>
<Value 2>0</Value 2>
<Value 3>1</Value 3>
<Value 4>0</Value 4>
</Parent 1>
<Parent 2>
<Value 1>1</Value 1>
<Value 2> 0</Value 2>
<Value 2> 0</Value 2>
<Value 3> 1</Value 3>
<Value 4> 0</Value 4>
</Parent 2>
Any ideas on how to do this?
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