[xsl] HowTo - Nested for-each XSLSort on multi-column display

[jdgarrett at alltel dot net]

-----Original Message-----
From: jdgarrett@alltel.net [mailto:jdgarrett@alltel.net]
Sent: Tuesday, April 10, 2001 11:54 AM
To: xml-dev@lists.xml.org
Subject: multi-column XSL:sort


Hey all...

Given the following XML source...
I need to construct the table that follows
but with the caveat that the PetNames are sorted
rather than just arranged in "document order"...

so I first have a xsl:for-each outer loop on
for each BreedType/Type (sorted of course) and then
I have an inner xsl:for-each loop on Type 
that also has a sort on the PetName attribute and
then shows just the PetName and the Age

(Note: so far I can do this when I do not
invoke any sorting on the inner for-each ...that
is ...I just loop through the document order
on Type...using select for the first column(PetName)
and following-sibling:: for the next column(Age)....
but I have yet to find a method in XSLT that will
let me sort on PetName and be able to access
the following-sibling element for the next sequence
of columns....

And yes I own Mike Kay's book .....

Does anyone know of a solution for this problem...

Sincerely
Jim Garrett
jdgarrett@alltel.net
=======================================================================

<Dogs>
    <BreedTypes>
        <Type>x</Type>
        <Type>y</Type>
        <Type>r</Type>
        <Type>t</Type>
        <Type>a</Type>
        <Type>d</Type>
    </BreedTypes>
    <DogName>
        <DogAge  Type="x" PetName="PetDog" >3</DogAge>
        <DogAge  Type="y" PetName="GuardsNothing">21</DogAge>
        <DogAge  Type="x" PetName="SnozzesAllDayLong">15</DogAge>
        <DogAge  Type="y" PetName="JustEats">5</DogAge>
        <DogAge  Type="y" PetName="DigsALot">8</DogAge>
        <DogAge  Type="x" PetName="Runner">7</DogAge>
        <DogAge  Type="x" PetName="Sleepy">5</DogAge>
        <DogAge  Type="r" PetName="Howler">4</DogAge>
        <DogAge  Type="t" PetName="Dog">3</DogAge>
        <DogAge  Type="xPetName="Bucket">2</DogAge>
    </DogName>
<Dogs>


so I want to be able to create the following table ..


BreedType = a

    (column 1)        (column 2)    (column 3)    (column 4)
        PetName         Age          PetName        Age  
-------------------------------------------------------------------------



BreedType = d
    (column 1)        (column 2)    (column 3)    (column 4)
        PetName         Age          PetName        Age  



-------------------------------------------------------------------------

BreedType = r
    (column 1)        (column 2)    (column 3)    (column 4)
        PetName         Age          PetName        Age  



-------------------------------------------------------------------------

BreedType = t
    (column 1)        (column 2)    (column 3)    (column 4)
        PetName         Age          PetName        Age  



-------------------------------------------------------------------------

BreedType = x
    (column 1)        (column 2)    (column 3)    (column 4)
        PetName         Age          PetName        Age  



-------------------------------------------------------------------------

BreedType = y
    (column 1)        (column 2)    (column 3)    (column 4)
        PetName         Age          PetName        Age  



-------------------------------------------------------------------------



        


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