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determine node position
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl] determine node position
- From: Kristof Bernaert <kbernaert at 1eEurope dot be>
- Date: Sun, 8 Apr 2001 15:15:37 +0200
- Reply-To: xsl-list at lists dot mulberrytech dot com
hi
with the value of an attribute i'm trying to determine the node position
number of the one element that contains that specific attribute value.
I tried already anything like this:
<xsl:when test="News/NewsBlock[@LABEL = '4']"><xsl:value-of
select="position()">
</xsl:when>
but in this case i get always node position 1.
how to determine the position towards the whole node-set ?
<week>
<item ID="monday"/>
<item ID="thuesday"/>
<item ID="wednesday"/>
<item ID="thursday"/>
<item ID="friday"/>
<item ID="saterday"/>
<item ID="sunday"/>
</week>
I want to now for example on which node position <item ID="thursday"/> is.
thx, kb
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