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RE: Ignoring Child Nodes using XPath
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] Ignoring Child Nodes using XPath
- From: "Ciaran Byrne" <ciaran dot byrne at 3tl dot com>
- Date: Mon, 26 Mar 2001 16:37:35 -0800
- Reply-To: xsl-list at lists dot mulberrytech dot com
Sorry,
I should have mentioned the fact that I'm not using the
XPath Query in an XSL stylesheet but rather to select the
node in MSXML i.e. dom.selectsinglenode("XPath Query").
I know I could concat the element together by getting the element
name and attributes but I thought there might have been a
more efficient solution using an XPath Query.
-----Original Message-----
From: owner-xsl-list@lists.mulberrytech.com
[mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Michael Kay
Sent: Monday, March 26, 2001 1:58 AM
To: xsl-list@lists.mulberrytech.com
Subject: RE: [xsl] Ignoring Child Nodes using XPath
> Is there a way in which I can
> select a node ignoring the child nodes
> as in the following example:
>
> What I have...
>
> <p align="left">
> Here <b>is</b> some content<br/>
> </p>
>
> What I want...
> <p alignt="left"></p>
There are many ways of ignoring the child nodes, in fact they will always be
ignored unless you specifically do something to access them.
Try
<xsl:template match="p">
<xsl:copy/>
<xsl:copy-of select="@*"/>
</xsl:template>
Mike Kay
Software AG
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