Re: [xsl] Not So Newbie XPath Question

[David Carlisle <davidc at nag dot co dot uk>]

> Mmm. Does using following-sibling work given Jeni Tennison's Post?

you can use any XPath expression inside a [] predicate. The axis
restriction only applies to step construction.

so you can't do
match="a/following-sibling::b]"
but you can do
match="b[preceding-sibling::a]
which matches what was intended, a b with an earlier a sibling.


(However I don't think Dave's stylesheet is doing quite what you asked
for)

David

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