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position of nodes
- To: "xsl" <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl] position of nodes
- From: "Partho Paul" <uk4u at rz dot uni-karlsruhe dot de>
- Date: Sat, 10 Feb 2001 12:52:40 +0100
- References: <200102011233370350.0104A42B@mailhost.rz.uni-karlsruhe.de>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Following problem: numbering nodes
I have the following xml-structure:
Chapter
/ \
/ \
/ \
Paragraph Paragraph
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
Text StretchText Text StretchText Text StretchText Text StretchText
1 2 3 4
What already works for the upper tree is with
<xsl:template match="StretchText">
<xsl:number level="any" />
</xsl:template>
or
<xsl:value-of select="count(preceding::StretchText) + 1"/>
Now I want to number the StretchText from the Paragraph node, which will look
like beneath:
Chapter
/ \
/ \
/ \
Paragraph Paragraph
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
/ | \ \ / | \ \
Text StretchText Text StretchText Text StretchText Text StretchText
1 2 1 2
How can that be done? Tried some modification of the above xsl, but nothing worked so far.
Thanx in advance!
_______________________________________________________________________
Partho Paul email: uk4u@rz.uni-karlsruhe.de
Computer science student or: paul@partho.de
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