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RE: How to copy all child elements except specific one?
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] How to copy all child elements except specific one?
- From: "Morris, Chris" <ChrisM at SNELLINGCORP dot COM>
- Date: Tue, 16 Jan 2001 13:58:58 -0600
- Reply-To: xsl-list at lists dot mulberrytech dot com
Okay - the following xsl does what I need. Is it GoodŽ, or can it be
improved upon?
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Level3">
<xsl:element name="Level3">
<xsl:copy-of select="*[not(name()='ChildElementToChange')]" />
<xsl:variable name="L3Attr" select="@L3Attr" />
<xsl:for-each select="ChildElementToChange">
<xsl:call-template name="ChangeChildElement">
<xsl:with-param name="L3Attr"><xsl:value-of select="$L3Attr"
/></xsl:with-param>
</xsl:call-template>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template name="ChangeChildElement">
<xsl:param name="L3Attr" />
<xsl:element name="ChildElementToChange">
<xsl:element name="NewElement">
<xsl:attribute name="L3Attr"><xsl:value-of select="$L3Attr"
/></xsl:attribute>
<xsl:attribute name="OldValue"><xsl:value-of select="@OldValue"
/></xsl:attribute>
<xsl:attribute name="NewValue"><xsl:value-of select="@NewValue"
/></xsl:attribute>
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
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